okay so 0.255 grams of a diprotic acid using 0.1023 M NaOH. 23.50 mL of NaOH required to reach second equivalence point.
1. At what volume of base added would the pH equal pKa2
2. At what volume of base added would the pH equal pKa1?
THANK YOU!!! :)
okay so 0.255 grams of a diprotic acid using 0.1023 M NaOH. 23.50 mL of NaOH required to reach second equivalence point.
1. At what volume of base added would the pH equal pKa2
2. At what volume of base added would the pH equal pKa1?
THANK YOU!!! :)
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